Range

Theoretical Maximum of DFT

Theoretical Maximum of DFT
  1. What is the range of DFT?
  2. What is the computational complexity of DFT?
  3. How is DFT calculated?
  4. What is the result of DFT?

What is the range of DFT?

The TDS normally provide a value or a range of values, e.g. 125 μm or 125 – 150 μm and usually refers to a single coat. If a scheme is 2 x 125 μm, the specified DFT (S DFT ) is 250 μm.

What is the computational complexity of DFT?

As multiplicative constants don't matter since we are making a "proportional to" evaluation, we find the DFT is an O(N2) computational procedure. This notation is read "order N-squared". Thus, if we double the length of the data, we would expect that the computation time to approximately quadruple.

How is DFT calculated?

The DFT formula for X k X_k Xk​ is simply that X k = x ⋅ v k , X_k = x \cdot v_k, Xk​=x⋅vk​, where x x x is the vector ( x 0 , x 1 , … , x N − 1 ) .

What is the result of DFT?

In mathematics, the discrete Fourier transform (DFT) converts a finite sequence of equally-spaced samples of a function into a same-length sequence of equally-spaced samples of the discrete-time Fourier transform (DTFT), which is a complex-valued function of frequency.

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