Howtosignalprocessing
- How do you find the Fourier series of a sine function?
- How do you find the discrete Fourier transform?
How do you find the Fourier series of a sine function?
Fourier Sine Series
bn=∫L0f(x)sinnπxLdx∫L0sin2nπxLdx=2L∫L0f(x)sinnπxLdx,n=1,2,3,…. f2(x)=−f(−x),−L<x<0f(x),0≤x≤L, obtained by extending f over [−L,L] as an odd function (Figure 11.3.
How do you find the discrete Fourier transform?
The DFT formula for X k X_k Xk is simply that X k = x ⋅ v k , X_k = x \cdot v_k, Xk=x⋅vk, where x x x is the vector ( x 0 , x 1 , … , x N − 1 ) .
